Calculating Kp using Kc – Equilibrium Constant Calculator


Calculating Kp Using Kc

Convert equilibrium constants between molar concentration and partial pressure


Molar concentration constant based on moles per liter.
Please enter a valid Kc value.


Standard calculations use 298.15 K (25°C).
Temperature in Kelvin must be greater than zero.


Sum of coefficients of gaseous products minus gaseous reactants.


Select based on the units of pressure required.

Calculated Kp
36.70
Temperature in Kelvin:
298.15 K
RT Product:
24.466
(RT)^Δn Multiplier:
24.466

Formula: Kp = Kc(RT)Δn

Kp Response to Temperature Change

This chart illustrates how Kp changes with temperature for the current Kc and Δn.

Kp Trend
Constant Kc Line

What is Calculating Kp using Kc?

Calculating Kp using Kc is a fundamental process in chemical thermodynamics and kinetics that allows scientists to relate the equilibrium constant expressed in terms of partial pressures (Kp) to the one expressed in molar concentrations (Kc). This relationship is vital because different experimental setups might measure gas amounts differently—some through concentration and others through total and partial pressure.

Who should use this? Chemistry students, chemical engineers, and researchers often find themselves calculating Kp using Kc when dealing with gaseous phase reactions. A common misconception is that Kp and Kc are always identical. However, they are only equal when the number of moles of gas on the reactant side equals the number of moles of gas on the product side (Δn = 0).

Calculating Kp using Kc Formula and Mathematical Explanation

The relationship between these two constants is derived from the Ideal Gas Law (PV = nRT). By rearranging the law to P = (n/V)RT, where (n/V) is molarity (C), we arrive at the standard conversion formula used when calculating Kp using Kc.

The formula is: Kp = Kc(RT)Δn

Variables used in Calculating Kp using Kc
Variable Meaning Unit Typical Range
Kp Equilibrium Constant (Pressure) Dimensionless (or atm/bar) 10⁻³⁰ to 10³⁰
Kc Equilibrium Constant (Concentration) Dimensionless (or mol/L) 10⁻³⁰ to 10³⁰
R Ideal Gas Constant L·atm/(K·mol) 0.08206 or 0.08314
T Absolute Temperature Kelvin (K) 100 K to 5000 K
Δn Change in Gaseous Moles Integer/Decimal -5 to +5

Practical Examples (Real-World Use Cases)

Example 1: Haber Process (Ammonia Synthesis)

Reaction: N₂(g) + 3H₂(g) ⇌ 2NH₃(g). Suppose Kc = 0.50 at 400°C (673.15 K). Here, Δn = 2 – (1 + 3) = -2. Using R = 0.08206.

  • Inputs: Kc = 0.50, T = 673.15 K, Δn = -2
  • Calculation: Kp = 0.50 * (0.08206 * 673.15)⁻²
  • Result: Kp = 0.50 * (55.24)⁻² = 0.50 * 0.000327 = 0.000163
  • Interpretation: The low Kp indicates that at this temperature, the partial pressure of products is significantly lower than the reactants at equilibrium.

Example 2: Decomposition of PCl₅

Reaction: PCl₅(g) ⇌ PCl₃(g) + Cl₂(g). Suppose Kc = 0.042 at 250°C (523.15 K). Here, Δn = (1 + 1) – 1 = 1.

  • Inputs: Kc = 0.042, T = 523.15 K, Δn = 1
  • Calculation: Kp = 0.042 * (0.08206 * 523.15)¹
  • Result: Kp = 0.042 * 42.93 = 1.803
  • Interpretation: Since Δn is positive, Kp is greater than Kc because the pressure terms increase the value of the equilibrium constant.

How to Use This Calculating Kp using Kc Calculator

Our tool simplifies the math involved in calculating Kp using Kc. Follow these steps:

  1. Enter the Kc value obtained from your concentration data.
  2. Input the Temperature of the system. You can switch between Celsius and Kelvin; the tool automatically handles the conversion to absolute temperature.
  3. Calculate Δn by subtracting the total moles of gaseous reactants from gaseous products.
  4. Select the appropriate Gas Constant (R). Use 0.08206 if your pressure is in atmospheres (atm).
  5. Review the primary highlighted result which updates in real-time as you type.

Key Factors That Affect Calculating Kp using Kc Results

When calculating Kp using Kc, several scientific factors influence the final numeric value:

  • Temperature Sensitivity: Since T is raised to the power of Δn, even small changes in temperature can cause massive shifts in Kp if Δn is large.
  • Stoichiometry (Δn): This is the most critical exponent. If Δn is zero, Kp = Kc regardless of temperature.
  • Units of R: Choosing the wrong gas constant (e.g., using 8.314 J/mol·K instead of 0.08206 L·atm/mol·K) will result in an incorrect Kp.
  • State of Matter: Only gaseous species are counted for Δn. Pure solids and liquids are excluded as their concentrations are constant.
  • Absolute Zero: Temperatures must be in Kelvin. A common error is calculating Kp using Kc with Celsius, leading to negative or undefined results.
  • Pressure Reference: The choice of R defines whether your calculated Kp is based on atmospheres, bar, or Pascals.
Common Δn Values for Chemical Reactions
Reaction Type Example Δn Value Kp vs Kc Relationship
Dimerization 2NO₂ → N₂O₄ -1 Kp < Kc
Decomposition CaCO₃(s) → CaO(s) + CO₂(g) +1 Kp > Kc
No Molar Change H₂ + I₂ → 2HI 0 Kp = Kc

Frequently Asked Questions (FAQ)

When does Kp equal Kc?
Kp equals Kc only when the change in moles of gas (Δn) is zero, meaning the number of gaseous product molecules equals the number of gaseous reactant molecules.
Can I use Celsius in the formula for calculating Kp using Kc?
No, the temperature must always be in Kelvin (absolute temperature) because the Ideal Gas Law relationship is based on thermodynamic absolute scales.
What R value should I use for calculating Kp using Kc?
Use 0.08206 L·atm/(mol·K) if you want the pressure in atmospheres, or 0.08314 L·bar/(mol·K) if you want the pressure in bar.
Do solids affect Δn when calculating Kp using Kc?
No. In equilibrium expressions, only species in the gaseous phase (g) are included when determining Δn for the conversion formula.
What if Δn is negative?
If Δn is negative, it means (RT) is in the denominator. This results in a Kp value that is smaller than the Kc value.
Is Kp unitless?
In modern thermodynamics, Kp and Kc are technically unitless as they are based on “activities” relative to a standard state (1 M or 1 atm), but in many textbooks, they carry units derived from the stoichiometry.
How does temperature increase affect Kp?
If Δn is positive, increasing T increases Kp relative to Kc. If Δn is negative, increasing T decreases Kp relative to Kc.
Why is calculating Kp using Kc important for engineering?
Engineers use these conversions to design reactor vessels where pressure limits are critical for safety and yield optimization.

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