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Square Root Calculator with Variables on Both Sides Worksheet

Reviewed by Calculator Editorial Team

This guide explains how to solve equations with square roots on both sides. We'll cover the step-by-step method, provide worked examples, and include a practice worksheet to help you master this algebraic technique.

Introduction

Equations with square roots on both sides can be challenging to solve, but with the right approach, they become manageable. This guide will walk you through the process of solving such equations, including when to square both sides and how to handle extraneous solutions.

Solving equations with square roots requires careful attention to detail. The key steps involve isolating one of the square roots, squaring both sides, and then solving for the variable. We'll cover these steps in detail and provide examples to illustrate each stage of the process.

Step-by-Step Method

Follow these steps to solve equations with square roots on both sides:

  1. Identify the equation with square roots on both sides.
  2. Isolate one of the square roots by moving all other terms to the other side of the equation.
  3. Square both sides of the equation to eliminate the square roots.
  4. Simplify the resulting equation by combining like terms.
  5. Solve for the variable by isolating it on one side of the equation.
  6. Check for extraneous solutions by plugging the solution back into the original equation.

Key Formula

If you have an equation like √(x + a) = √(b - x), follow these steps to solve for x:

  1. Square both sides: x + a = b - x
  2. Combine like terms: 2x = b - a
  3. Solve for x: x = (b - a)/2

Remember that squaring both sides of an equation can introduce extraneous solutions, so it's essential to verify your solutions by plugging them back into the original equation.

Worked Examples

Example 1

Solve the equation: √(x + 5) = √(10 - x)

  1. Square both sides: x + 5 = 10 - x
  2. Combine like terms: 2x = 5
  3. Solve for x: x = 2.5
  4. Check the solution: √(2.5 + 5) = √(10 - 2.5) → √7.5 = √7.5 (valid)

Example 2

Solve the equation: √(2x + 3) = √(x + 7) + 1

  1. Isolate one square root: √(2x + 3) - √(x + 7) = 1
  2. Square both sides: (2x + 3) - 2√[(2x + 3)(x + 7)] + (x + 7) = 1
  3. Simplify: 3x + 10 - 2√[(2x + 3)(x + 7)] = 1
  4. This leads to a more complex equation that may require additional steps to solve.

Note

Some equations with square roots on both sides may require additional steps or techniques to solve completely. Always verify your solutions by plugging them back into the original equation.

Practice Worksheet

Use this worksheet to practice solving equations with square roots on both sides. Try to solve each equation using the method described in this guide.

  1. √(x + 4) = √(12 - x)
  2. √(3x + 2) = √(x + 8) + 1
  3. √(2x - 1) = √(x + 5) + 2
  4. √(x + 6) = √(x + 2) + √(x - 2)
  5. √(x + 7) = √(x + 3) + √(x - 1)

After attempting these problems, you can use our calculator to check your answers and see the step-by-step solutions.

Frequently Asked Questions

When do I need to square both sides of an equation with square roots?

You should square both sides when you have square roots on both sides of the equation and you want to eliminate the square roots to simplify the equation.

What are extraneous solutions in equations with square roots?

Extraneous solutions are solutions that emerge from the solving process but do not satisfy the original equation. This can happen when you square both sides of an equation, as squaring can introduce additional solutions that aren't valid in the original context.

How do I know if a solution is extraneous?

To check if a solution is extraneous, substitute the solution back into the original equation. If the equation holds true, the solution is valid. If it doesn't, the solution is extraneous and should be discarded.

Can I always solve equations with square roots on both sides?

Not all equations with square roots on both sides can be solved using basic algebraic methods. Some may require more advanced techniques or may not have real solutions. Always verify your solutions and consider the context of the problem.