Use the Voltage-Division Principle to Calculate V in Figure P2.38 | Circuit Calculator


Voltage-Division Principle Calculator

Use the voltage-division principle to calculate v in figure p2.38 and other series circuits


Total voltage supplied by the source (Volts).
Please enter a valid voltage.


Resistance of the first component.
Resistance cannot be negative.


Resistance of the second component.
Resistance cannot be negative.


Resistance of the third component.
Resistance cannot be negative.


Select which resistor represents ‘v’ in your diagram.


Calculated Voltage (v)

40.00 V

Based on the Voltage-Division Principle formula: v = Vs * (Rtarget / Rtotal)

Total Circuit Resistance (Rtotal): 60.00 Ω
Circuit Current (I): 2.00 A
Power Dissipated by Target: 80.00 W

Voltage Distribution Diagram

Chart showing relative voltage drops across R1, R2, and R3.

Understanding How to Use the Voltage-Division Principle to Calculate V in Figure P2.38

In electrical engineering, the ability to use the voltage-division principle to calculate v in figure p2.38 is a foundational skill. Whether you are a student working through Nilsson and Riedel’s “Electric Circuits” or a technician troubleshooting a sensor network, understanding how potential drops across series components is vital. This principle allows us to determine the voltage across any individual resistor in a series string without first having to calculate the current flowing through the loop.

The voltage-division principle is a direct consequence of Kirchhoff’s Voltage Law (KVL) and Ohm’s Law. When resistors are connected in series, the same current flows through each one, but the source voltage is distributed among them proportional to their resistance values.

The Mathematical Foundation of Voltage Division

To use the voltage-division principle to calculate v in figure p2.38, we use a derivation based on Ohm’s Law (V = IR). In a series circuit with a source voltage $V_s$ and resistors $R_1, R_2, … R_n$:

  1. Calculate Total Resistance: $R_{total} = R_1 + R_2 + … + R_n$
  2. Determine Circuit Current: $I = V_s / R_{total}$
  3. Calculate specific voltage $v_x$ across $R_x$: $v_x = I \times R_x$
  4. Substitute current: $v_x = V_s \times (R_x / R_{total})$
Variable Description Unit Typical Range
Vs Source Voltage Volts (V) 1V – 480V
Rx Resistance of target component Ohms (Ω) 1Ω – 10MΩ
Rtotal Sum of all series resistances Ohms (Ω) Sum of Rn
v Output Voltage (Drop) Volts (V) 0 – Vs

Table 1: Key parameters required to use the voltage-division principle to calculate v in figure p2.38.

Practical Examples

Example 1: A circuit has a 24V source and two resistors, R1 = 100Ω and R2 = 300Ω. We want to find the voltage across R2. Using the principle: $v = 24 \times (300 / (100+300)) = 24 \times 0.75 = 18V$.

Example 2: In a specific textbook problem like Figure P2.38, you might have three resistors: 2kΩ, 5kΩ, and 3kΩ with a 10V source. To find the voltage across the 5kΩ resistor: $v = 10 \times (5 / (2+5+3)) = 10 \times 0.5 = 5V$.

How to Use This Voltage-Division Calculator

This tool is designed to help you quickly use the voltage-division principle to calculate v in figure p2.38 or any custom series circuit. Follow these steps:

  • Input Source Voltage: Enter the DC or RMS AC voltage of your power supply.
  • Enter Resistance Values: Provide the values for up to three resistors in the series chain. If your circuit has fewer, set the remaining values to zero (though in a real circuit, a zero-ohm resistor is a short).
  • Select the Target: Choose which resistor or combination of resistors represents the “v” you are solving for.
  • Review Results: The calculator updates in real-time to show the voltage, total resistance, and current.

Key Factors Affecting Voltage Division

  • Resistance Ratios: The voltage drop is entirely dependent on the ratio of the target resistor to the total resistance, not just the absolute values.
  • Source Stability: If the source voltage fluctuates, all divided voltages will fluctuate proportionally.
  • Load Resistance: Adding a load in parallel with your target resistor (like a voltmeter with low impedance) will change the effective resistance and ruin the calculation.
  • Temperature: Resistance changes with temperature, which can shift the voltage division in precision circuits.
  • Tolerance: Real-world resistors have 1% or 5% tolerances, meaning actual voltage may vary slightly from theoretical calculations.
  • Frequency: In AC circuits with inductors or capacitors, impedance (Z) replaces resistance, but the division principle remains similar.

Frequently Asked Questions

Q: Can I use this for parallel circuits?
A: No. Voltage is the same across all branches of a parallel circuit. For parallel circuits, you use the Current-Division Principle.

Q: What if one resistor is significantly larger than the others?
A: That resistor will “swamp” the others, and the voltage across it will be nearly equal to the source voltage.

Q: Does the order of resistors matter?
A: No. In a series circuit, the total resistance and individual drops remain the same regardless of the physical order of $R_1, R_2, R_3$.

Q: Why is my calculated voltage higher than my source?
A: This is mathematically impossible in a passive resistive circuit. Check if you entered negative resistance values or made an error in the sum.

Q: How do I calculate v if the resistors are in kΩ?
A: You can enter them as kΩ as long as *all* values are in kΩ, or convert them all to Ohms (e.g., 2.2k = 2200).

Q: What is Figure P2.38?
A: It typically refers to a standard problem in “Electric Circuits” by Nilsson/Riedel, which asks students to apply the divider rule to a series-parallel hybrid or a specific series loop.

Q: Is this principle applicable to AC?
A: Yes, for purely resistive AC circuits. For circuits with reactance, use complex impedances.

Q: What happens if I short-circuit one resistor?
A: Its resistance becomes 0Ω, and the voltage drop across it becomes 0V. The remaining voltage is redistributed among the other resistors.

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