Clausius Clapeyron Equation Calculator | Vapor Pressure & Phase Change


Clausius Clapeyron Equation Calculator

Calculate Vapor Pressure and Temperature Changes with Precision


Standard atmospheric pressure is 101.325 kPa or 1 atm.
Please enter a positive pressure value.


Commonly the normal boiling point (e.g., 100°C for water).


Energy required to vaporize one mole (e.g., 40.65 kJ/mol for water).
Enthalpy must be a positive number.


The temperature at which you want to find the new vapor pressure.


Predicted Vapor Pressure (P₂)
198.48
kPa
T₁ in Kelvin: 373.15 K
T₂ in Kelvin: 393.15 K
1/T₁ – 1/T₂: 0.0001364 K⁻¹

Vapor Pressure vs. Temperature Curve

The blue line represents the exponential increase in vapor pressure as temperature rises.

What is the Clausius Clapeyron Equation Calculator?

The clausius clapeyron equation calculator is an essential tool for chemists, engineers, and students to estimate the vapor pressure of a substance at a specific temperature. The Clausius-Clapeyron equation describes the relationship between the vapor pressure of a liquid and its temperature, providing a way to predict phase transitions.

Who should use this calculator? It is widely used by laboratory researchers to predict boiling points under vacuum, by meteorologists to understand water vapor in the atmosphere, and by chemical engineers designing distillation columns. A common misconception is that vapor pressure increases linearly with temperature; however, as the clausius clapeyron equation calculator demonstrates, the relationship is actually exponential.

Clausius Clapeyron Equation Formula and Mathematical Explanation

The Clausius-Clapeyron equation is derived from the Clapeyron equation by assuming the vapor behaves as an ideal gas and the volume of the liquid is negligible compared to the vapor. The integrated form used in our clausius clapeyron equation calculator is:

ln(P₂ / P₁) = (-ΔHᵥₐₚ / R) * (1/T₂ – 1/T₁)

Variable Meaning Unit Typical Range
P₁ Initial Vapor Pressure kPa, atm, mmHg 0.001 – 500
P₂ Final Vapor Pressure Matches P₁ Calculated
T₁ Initial Temperature Kelvin (K) 100 – 1000 K
T₂ Final Temperature Kelvin (K) 100 – 1000 K
ΔHᵥₐₚ Enthalpy of Vaporization kJ/mol 10 – 100 kJ/mol
R Ideal Gas Constant 8.314 J/(mol·K) Constant

Practical Examples (Real-World Use Cases)

Example 1: Water at High Altitude

Imagine you are at a high altitude where water boils at 90°C. You want to know the atmospheric pressure. Using the clausius clapeyron equation calculator, you input P₁ = 101.325 kPa, T₁ = 100°C (373.15 K), ΔHᵥₐₚ = 40.65 kJ/mol, and T₂ = 90°C (363.15 K). The calculator will output a pressure of approximately 70.1 kPa, which is the ambient pressure at about 3,000 meters elevation.

Example 2: Industrial Chemical Storage

A storage tank contains Ethanol with a vapor pressure of 5.95 kPa at 20°C. If the sun heats the tank to 45°C, what is the new pressure? By entering these values into the clausius clapeyron equation calculator (with ethanol’s ΔHᵥₐₚ ≈ 38.6 kJ/mol), you can predict the pressure increase to ensure the tank’s relief valves are correctly rated.

How to Use This Clausius Clapeyron Equation Calculator

  1. Enter Initial Pressure (P₁): Provide the known vapor pressure at a specific temperature.
  2. Enter Initial Temperature (T₁): Enter the temperature corresponding to P₁. Note that our tool converts °C to Kelvin automatically.
  3. Specify Enthalpy (ΔHᵥₐₚ): Input the heat of vaporization for your specific substance.
  4. Set Target Temperature (T₂): Enter the temperature where you need to find the new pressure.
  5. Read the Result: The clausius clapeyron equation calculator updates in real-time to show P₂ and intermediate steps.

Key Factors That Affect Clausius Clapeyron Equation Results

  • Intermolecular Forces: Substances with stronger hydrogen bonding (like water) have higher ΔHᵥₐₚ, leading to steeper pressure curves in the clausius clapeyron equation calculator.
  • Temperature Range: The equation assumes ΔHᵥₐₚ is constant over the temperature range. Over very large gaps, accuracy may decrease.
  • Ideal Gas Assumption: The math assumes the vapor behaves ideally. At very high pressures near the critical point, this tool may deviate from experimental data.
  • Purity of Substance: Impurities or solutes will change the vapor pressure (Raoult’s Law), which isn’t accounted for in the basic equation.
  • Unit Consistency: Ensure R (8.314 J/mol·K) matches the energy unit of ΔHᵥₐₚ (convert kJ to J).
  • Phase Identification: This specific formula is for liquid-gas transitions. Sublimation (solid-gas) uses the Enthalpy of Sublimation.

Frequently Asked Questions (FAQ)

1. Why is the natural log (ln) used in the equation?

The ln appears because the relationship between pressure and temperature involves integrating 1/P during the derivation from the Clapeyron equation.

2. Can I use this for sublimation?

Yes, but you must replace the enthalpy of vaporization with the enthalpy of sublimation in the clausius clapeyron equation calculator.

3. Is the result accurate near the critical point?

No, the Clausius-Clapeyron equation is an approximation that breaks down as you approach the critical temperature and pressure.

4. Why does the calculator require Kelvin?

Thermodynamic equations require absolute temperature scales. Using Celsius would result in division by zero or negative values, breaking the physics.

5. How does ΔHᵥₐₚ change with temperature?

In reality, ΔHᵥₐₚ decreases as temperature increases, reaching zero at the critical point. Our clausius clapeyron equation calculator uses a constant average value for simplicity.

6. Can I solve for T₂ instead?

While this specific UI solves for P₂, you can rearrange the formula: 1/T₂ = 1/T₁ – (R * ln(P₂/P₁) / ΔHᵥₐₚ).

7. What is the R value in the calculator?

We use the universal gas constant R = 8.31446 J/(mol·K).

8. What units should I use for pressure?

You can use any unit (kPa, atm, mmHg) as long as P₁ and P₂ use the same unit.

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